Question

If during revolving around the Earth’s orbit, the mass of a satellite is doubled due to any reason, then what would be the effect on time period?

Answer 1

The time period of the satellite,
T = \(2 \pi \sqrt{\frac{r^{3}}{G M}}\)
where, r = radius of the orbit,
M mass of Earth.
In above formula, the mass of the satellite (m) is not used. Therefore the time period T will not depend on m. Hence, on doubling the mass of the satellite, its time period will remain unchanged.