The kinetic energy of the satellite,
K = \(\frac{1}{2} \frac{G M m}{r}\)
If the kinetic energy is increased by 100%, then
Therefore, the binding energy of the satellite in this new situation
Et = K’ + U = \(\frac{G M m}{r}-\frac{G M m}{r}\) = 0
or Et = 0
Therefore the satellite will escape.