Given; distance between Earth and Sun,
r = 108 km = 1011 m
Mass of Sun, Ms = 3.24 × 105Me
The distance of Lagrangian Point from the Earth x =?
A Lagrangian point P,
or x (568.8 + 1) = 1011
or x × 569.8 = 1011
∴ x = \(\frac{10^{11}}{569.8}=\frac{1000}{569.8} \times 10^{8}\)
or x = 1.75 × 108 m