The above question can be written as,= t – 2t – 5 – 5 + 10t = 6 + 8t – 3t + 12
Now, find the value of t by considering the above equation,
Transposing -5, -5 to RHS and it becomes 5, 5 and 8t, -3t to LHS it becomes -8t, 3t
= t – 2t + 10t – 8t + 3t = 6 + 12 + 5 + 5
= 14t – 10t = 28
= 4t = 28
Multiplying both side by (1/4),
= 4t × (1/4) = 28 × (1/4)
= t = 7
By substituting 7 in the place of t in given equation, we get
LHS,
= t – 2t – 5 – 5 + 10t
= 7 – 2× (7) – 5 – 5 + 10(7)
= 7 – 14 – 5 – 5 + 70
= 77 – 24
= 53
RHS,
= 6 + 8t – 3t + 12
= 6 + 8 × (7) – 3 × (7) + 12
= 6 + 56 – 21 + 12
= 74 – 21
= 53
By comparing LHS and RHS
= 15 = 15
∴ LHS = RHS
Hence, the result is verified.
