Let the required three consecutive positive even integers be x, (x + 2) and (x + 4)Then,
= x + (x+2) + (x+4) = 90
= x + x + 2 + x + 4 = 90
= 3x + 6 = 90
Transposing 6 to LHS and it becomes – 6
= 3x = 90 -6
= 3x = 84
Multiplying both side by (1/3)
= 3x × (1/3) = 90 × (1/3)
= x = 30
The other numbers are (x + 2) = 30 + 2 = 32 and (x + 4) = 30 + 4 = 34
∴ The required three consecutive positive even integers are 30, 32 and 34
