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If (2n + 5) = 3(3n – 10), then z =? (a)5 (b)3 (c)(2/5) (d)(2/5)

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If (2n + 5) = 3(3n – 10), then z =?

(a)5 (b)3 (c)(2/5) (d)(2/5)

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(a) 5

Because,

= 2n + 5 = 9n – 30

Transposing 2n to RHS and it becomes – 2n and -30 to LHS it becomes 30

= 30 + 5 = 9n -2n

= 35 = 7n

Multiplying both side by (1/7).

= 35 × (1/7) = 7n × (1/7)

= 5 = n

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