Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Rigid Body Dynamics by (49.6k points)
closed by

Calculate the moment of inertia of a symmetrical thin rod along the axis passing through its end and perpendicular to its length.

1 Answer

+1 vote
by (34.7k points)
selected by
 
Best answer

Moment of Inertia of a Thin Rod

Moment of Inertia of a Thin Rod about the Axis Perpendicular to the Length and Passing through the Center
Take a uniform thin rod AB whose mass is M and length is l. YY’ axis passes through the center of the rod and perpendicular to the length of the rod. We have to calculate the moment of inertia about this axis YY’.

Fig: Moment of Inertia of a thin rod about the perpendicular axis along its length

Suppose, small piece dx is at a distance x from the YY’ axis. Hence, mass of length dx is = \(\left(\frac{M}{l}\right)\) dx
The moment of inertia of small piece about the YY’ axis
dl = \(\left[\left(\frac{M}{l}\right) d x\right] x^{2}\)
Therefore, the moment of inertia of the complete rod about the YY’ axis.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...