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 An ore contains 12 % copper. How many kilograms of the ore required to get 69 kg of copper?

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 An ore contains 12 % copper. How many kilograms of the ore required to get 69 kg of copper?

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Let x kg be the amount of required ore,

Now, 12% of x kg = 69 kg

= (12/100) × (x) = 69 kg

= x = (69 × 100) / 12

= x = 575 kg

Hence, 575 kg of ore is required to get 69 kg copper.

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