Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
6.1k views
in Profit and Loss by (49.9k points)
closed by

Find the SP when CP = ₹ 8640, loss = 12(1/2) %.

1 Answer

0 votes
by (48.6k points)
selected by
 
Best answer

CP = ₹ 8640, loss = 12(1/2) %

We have,

SP = {((100 – loss %) /100) × CP)}

= {((100 – (25/2)) /100) × 8640)}

= {(((200 – 25)/2)) /100) × 8640)}

= {((175/2) /100) × 8640}

= {((175/2) × (1/100)) × 8640}

= {(175/200) × 8460}

= {1512000/200}

= ₹7560

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...