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Prove that measure of each angle of an equilateral triangle is 600

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Let ∆ABC be an equilateral triangle, then we have

AB = BC = CA ...(i) 

∴ AB = BC 

∴ ∠C = ∠A ...(ii) [Angles opposite to equal sides are equal] 

 Also, BC = CA 

∴ ∠A = ∠B ...(iii) [Angles opposite to equal sides] 

 By (ii) & (iii) we get ∠A = ∠B = ∠C 

 Now in ∆ABC ∠A + ∠B + ∠C = 1800 

⇒ 3∠A = 1800 [∴∠A = ∠B = ∠C] 

⇒ ∠A = 600 = ∠B = ∠C 

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