Let ∆ABC be an equilateral triangle, then we have
AB = BC = CA ...(i)
∴ AB = BC
∴ ∠C = ∠A ...(ii) [Angles opposite to equal sides are equal]
Also, BC = CA
∴ ∠A = ∠B ...(iii) [Angles opposite to equal sides]
By (ii) & (iii) we get ∠A = ∠B = ∠C
Now in ∆ABC ∠A + ∠B + ∠C = 1800
⇒ 3∠A = 1800 [∴∠A = ∠B = ∠C]
⇒ ∠A = 600 = ∠B = ∠C