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In the given figure, rays OA, OB, OC and OD are such that ∠AOB = 50°, ∠BOC = 90°, ∠COD = 70° and ∠AOD = x°.

(a) 50o (b) 70o (c) 150o (d) 90o

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Best answer

(c) 150o

Because,

We know that the complete angle is equal to the sum of all angles is equal to 360o.

∴ ∠AOB + ∠BOC + ∠COD + ∠AOD = 360o

= 50o + 90o + 70o + xo = 360o

= xo + 210o = 360o

= xo = 360o – 210o

= xo = 150o

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