Given υ = 100 ms-1; α = 22 cm = 0.22m; n = 100Hz
\(\therefore \) \(\lambda = \frac{v}{n} = \frac{100}{100} = 1 m\)
∴ Equation of simple harmonic wave moving in positive x- direction
For t = 5s and x = 2 m but y = 0
f = \(\omega^2 \times 0 = 0\)
f = 0