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A simple harmonic wave is moving towards the positive ac-direction with 100 m/s velocity. Amplitude of wave is 22 cm and the frequency is 100 vibrations/second (Hz). Calculate the displacement, velocity and acceleration of a particle which is at a distance x = 2 m from the origin at t = 5 seconds.

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Given υ = 100 ms-1; α = 22 cm = 0.22m; n = 100Hz

\(\therefore \) \(\lambda = \frac{v}{n} = \frac{100}{100} = 1 m\)

∴ Equation of simple harmonic wave moving in positive x- direction

For t = 5s and x = 2 m but y = 0

f = \(\omega^2 \times 0 = 0\)

f = 0

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