Let CE is a pole of height h meter. AD is a hill of height 200 m.
Let distance between bottom of hill to pole = x m.
According to question
∠XAC= 30° = ∠ACB and ∠XAE = 60° = ∠AED
From right angled ∆ADE
tan 60° = AD/DE
⇒ √81 = 200/x
⇒ x = 200/√3 m
From right angled ∆ABC,
Hence, height of pole = 133.33 m.