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In ∆ABC, AD is a median and P is a point is AD such that AP : PD = 1 : 2 then the area of ∆ABP =

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In ∆ABC, AD is a median and P is a point is AD such that AP : PD = 1 : 2 then the area of ∆ABP = 

(A) 1/2 × Area of ∆ABC 

(B) 2/3 × Area of ∆ABC 

(C) 1/3 × Area of ∆ABC 

(D) 1/6 × Area of ∆ABC 

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The correct option is (D).
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