It is given that
R = {(a, b): a, b ∈ Z and (a + b) is even}
Reflexive:
If a ∈ Z then a + a = 2a, which is even
So we get (a, a) ∈ R
Therefore, it is reflexive.
Symmetric:
Consider (a, b) ∈ Z then a + b is even
The same way b + a is also even.
So we know that (b, a) also belongs to R.
We get (a, b) ∈ R and (b, a) ∈ R
Therefore, R is symmetric.
Transitive:
Consider (a, b) and (b, c) ∈ R then a + b = 2k and b + c = 2r is even
By adding them
a + 2b + c = 2k + r
We get
a + c = 2 (k + r – b)
So a + c is even (a, c) ∈ R
Therefore, R is transitive.
We know that R is reflexive, symmetric and transitive.
Therefore, R is equivalence.