Given: A circle with centre O. Chords PQ and RS subtend equal angles at the enter of the circle.
i.e. ∠POQ = ∠ROS
To Prove : Chord PQ = chord RS.
Proof : In ∆POQ and ∆ROS,
∠POQ = ∠ROS [Given]
OP = OR [Radii of the same circle]
OQ = OS [Radii of the same circle]
⇒ ∆POQ ≅ ∆ROS [By SSS]
⇒ chord PQ = chord RS [By cpctc]