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Let f: R → R: f(x) = (2x + 1) and g: R → R: g(x) = (x2 – 2).

Write down the formulae for

(i) (g o f) (ii) (f o g) (iii) (f o f) (iv) (g o g).

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Best answer

It is given that

f(x) = (2x + 1) and g(x) = (x2 – 2)

(i) g o f = g o f (x) = g{f(x)} = g {2x + 1}

So we get

= (2x + 1)2 – 2

It can be written as

= 4x2 + 4x + 1 – 2

On further calculation

= 4x2 + 4x – 1

(ii) f o g = f o g (x) = f {g(x)} = f{x2 – 2}

So we get

= 2 {x2 – 2} + 1

It can be written as

= 2x2 – 4 + 1

On further calculation

= (2x2 – 3)

(iii) f o f = f o f (x) = f{f(x)} = f(2x + 1)

So we get

= 2 (2x + 1) + 1

It can be written as

= 4x + 2 + 1

On further calculation

= 4x + 3

(iv) g o g = g o g (x) = g{g(x)} = g { x2 – 2}

So we get

= (x2 – 2)2 – 2

On further calculation

= x4 – 4x2 + 4 – 2

We get

= x4 – 4x2 + 2

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