**We know that**

f (2) = 7, f (3) = 9, f(4) = 11 and f (5) = 13

Here dom (f) = {2, 3, 4, 5} = A and range (f) = {7, 9, 11, 13} = B

So different element in A have different image.

f is one-one.

range (f) = B where f is onto

**Hence, f is one-one onto and invertible.**

We know that

f (2) = 7, f (3) = 9, f(4) = 11 and f (5) = 13

So we get

f ^{-1} (7) = 2, f ^{-1} (9) = 3, f ^{-1} (11) = 4, f ^{-1} (13) = 5

**Therefore, f **^{-1} {(7, 2), (9, 3), (11, 4), (13, 5)}.