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+1 vote
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in Trigonometry by (49.9k points)
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Find the principal value of:

(i) tan -1 (1/√3)

(ii) sec -1 (2/√3)

(iii) cosec -1 (√2)

1 Answer

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Best answer

(i) tan -1 (1/√3)

We know that

tan -1 (1/√3) = tan -1 (tan π/6)

= π/6

(ii) sec -1 (2/√3)

We know that

sec -1 (2/√3) = sec -1 (sec π/6)

= π/6

(iii) cosec -1 (√2)

We know that

cosec -1 (√2) = cosec -1 (cosec π/4)

= π/4

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