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Find the principal value of

(i) sin -1 (-1/ √2)

(ii) cos -1 (-√3/ 2)

(iii) tan -1 (-√3)

(iv) sec -1 (-2)

(v) cosec -1 (- √2)

(vi) cot -1 (-1/ √3)

1 Answer

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Best answer

(i) sin -1 (-1/ √2)

We know that

sin -1 (-1/ √2) = – sin -1 (sin π/4)

= – π/4

(ii) cos -1 (-√3/ 2)

We know that

cos -1 (-√3/ 2) = π – cos -1 (cos π/6)

= π – π/6

= 5π/6

(iii) tan -1 (-√3)

We know that

tan -1 (-√3) = – tan -1 (tan π/3)

= – π/3

(iv) sec -1 (-2)

We know that

sec -1 (-2) = π – sec -1 (sec π/3)

= π – π/3

= 2 π/3

(v) cosec -1 (- √2)

We know that

cosec -1 (- √2) = – cosec -1 (cosec π/4)

= – π/4

(vi) cot -1 (-1/ √3)

We know that

cot -1 (-1/ √3) = π – cot -1 (cot π/3)

= π – π/3

= 2 π/3

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