Let required point is P(x, y)
Given AP = 3/7AB ……(i)
But PB = AB – AP
= AB – 3/7AB
= (7AB - 3AB)/7
PB = 4/7AB ……(ii)
From equation (i) and (ii)
AP : PB = 3/7AB : 4/7AB
AP : PB = 3 : 4
∴ Hence point P divides point A and B in the ratio 3 : 4 respectively.
∴ Hence co-ordinate of point P.
Hence co-ordinate of point P = (-2/7, -20/7)