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If a parallel plate capacitor has a capacity C, on inserting a dielectric slab of relative permeability K and thickness equal to one-fourth of the plate separation is placed between the plates, then its capacity becomes C'. The value of C'/C will be;

{A} K/2(K+1)

{B} 2K/(K+1)

{c}5k/(4k+1)

{d} 4k/(3k+1)

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1 Answer

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Answer: (d) 4k/(3k+1)

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