Steps of construction :
(1) First of all, we draw a circle with center O and radius 2.5 cm
(2) Take a point P a part 6.5 cm from the center of circle and join OP.
(3) Draw a perpendicular bisector of PO and mark the point M.
(4) Taking M as center and radius and draw a circle which intersects their circle center O at A and B.
(5) Join PA and PB.
Hence PA and PB are the required tangents.
On measuring we get PA = PB = 6.0 cm.
Calculation to find the length of tangents :
In ∆POA
∠PAO = 90°
So ∆POA is a right angled triangle,
So by the Pythagoras Theorem,
PO2 = AO2 + PA2
⇒ PA2 = PO2 – AO2
= (6.5)2 – (2.5)2
= 42.25 – 6.25
⇒ PA2 = 36.00
∴ PA = \(\sqrt { 36 }\) = 6 cm
Hence, the length of each tangent is 6.0 cm.