Given :
Equilateral ∆ABC whose each side is 5 cm in length.
Steps of construction :
(1) Draw a line segment BC = 5 cm.
(2) Taking B as center and radius 5 cm draw an arc.
(3) Taking C as center and radius 5 cm draw another arc which intersects the first arc at A.
(4) Join AB and AC. ∠ABC is an equilateral triangle.
(5) Draw the perpendicular bisectors of AC and AB which intersect each other at O. O is the circumcentre of ∆ABC. Join O to B.
(6) Taking O as center and radius equal to OA draw a circle which passes through three vertices of ∆ABC.
