Given :
∆ABC in which AB = 45 cm, AC = 7.5 cm and ∠P = 90°
Steps of construction :
(1) Draw a line segment AB = 45 cm
(2) Construct ∠ABX = 90°.
(3) Taking A as center and radius 7.5 draw an arc which intersects BX to C.
(4) Join AC ∆ABC is required triangle.
(5) Draw the bisectors of ∠A and ∠B which intersects each other at I.
(6) From I draw IP ⊥ AB.
(7) Taking I as center and IP as radius draw the circle which touches the three sides of ∆ABC.
Hence this is the required in circle of ∆ABC.
