Given :
In ∆ABC, BC =5 cm, ∠B = 90°, CA = 7 cm.
To contract: In circle of ∆ABC.
Steps of construction:
(1) First of all draw line segment BC = 5 cm.
(2) Draw a ray BX making an angle of 90° at B of BC.
(3) Taking C as center and radius 7 cm draw an arc which intersects BX at A. Join A to C.
It is the ∆ABC given.
(4) Draw the perpendicular bisectors of AB and AC, which intersect each other at O. Join O to A.
(5) Taking O as center and OA as radius draw a circle which passes through three vertices. It is the required circle.
