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A short-sighted person cannot see clearly beyond 5m. Calculate the power of lens required to correct his vision to normal?

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f  = – 5m

P = \(\frac { 1 }{ f }\) = –\(\frac { 1 }{ 5 }\) 

= 0.20 =0.20

∴ Power = 0.2 Dioptre

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