Given: Side of square = 14 cm
Diameter of semi circle (AD = CB) = 14 cm
Radius of semicircle (R) = \(\frac { 14 }{ 2 }\) = 7 cm
∴ Area of square ABCD = (side)2
= 14 × 14 = 196 cm2
Area of semicircle = \(\frac { 1 }{ 2 }\)πr2
\(\frac { 1 }{ 2 }\) × \(\frac { 22 }{ 7 }\) × 7 × 7 = 77 cm2
Area of two semicircle =2 × 77 = 154 cm2
∴ Area of shaded part Area of square ABCD – Area of two semicircles
= 196 – 154 = 42 cm2
Thus area of shaded part 42 sq cm
