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4.2k views
in Geometry by (49.9k points)
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In Fig., PQ ⊥ RQ, PQ = 5 cm and QR = 5 cm. Then ∆ PQR is

(A) a right triangle but not isosceles

(B) an isosceles right triangle

(C) isosceles but not a right triangle

(D) neither isosceles nor right triangle

1 Answer

+1 vote
by (51.6k points)
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Best answer

(B) an isosceles right triangle

From the question it is given that, PQ ⊥ RQ, PQ = 5 cm and QR = 5 cm.

We know that, isosceles triangle has two equal side.

Therefore, the given ΔPQR is an isosceles right triangle.

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