Here, if we consider the required triangle to be ΔABC, as shown alongside.
Clearly, AB = 3.8cm, ∠B = 900 and BC + AC = 6cm.
STEPS :
(i) Draw AB = 3.8cm
(ii) Through B, draw line BP so that ∠ABP = 900
(iii) From BP, cut BD = 6cm
(iv) Join A and D.
(v) Draw perpendicular bisector of AD, which meets BD at point C.
Thus, ABC is the required triangle.
Case (iii) When the base of the triangle, one base angle and the difference of the other two sides are given.
