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in Measures of Central Tendency by (34.1k points)
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If median of given data is 28.5 then find the values of x and y.

Class-interval 0-10 10-20 20-30 30-40 40-50 50-60 Total
Frequency 5 x 20 15 y 5 80

1 Answer

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Best answer

cumulative frequency table

But sum of frequency Σfi = N = 80 

which is equal to last term of c.f. group

∴ 45 + x + y = 80 or x + y = 80 – 45

⇒ x + y = 35 …(i)

Now \(\frac { N }{ 2 }\) = \(\frac { 80 }{ 2 }\) = 40

and median of distribution = 28.5 

which lies in class-interval 20 – 30.

Median class = 20 – 30

l = 20, f = 20, c = 5 + x and h = 10

57 = 75 – x or x = 18

Putting value of x in eqn. (i), 

18 + y = 35

Thus, y = 17.

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