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in Measures of Central Tendency by (31.2k points)
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Median of following data is 525. If sum of frequencies is 100, then  find values of x and y. 

Class - interval 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000
Frequency 2 5 x 12 17 20 y 9 7 4

1 Answer

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Best answer

Given: Σf = N = 100

Thus, 76 + x + y = 100

⇒ x + y = 100 – 76 = 24 …..(i)

Median is 525 which lies in 500 – 600.

∴ l = 500; f = 20, c = 36 + x, and h = 100

⇒ 25 = (14 – x) × 5

⇒ 14 – x = \(\frac { 25 }{ 5 }\) = 5

⇒ x = 14 – 5

∴ x = 9

From equation (i), 9 + y = 24

⇒ y = 24 – 9

∴ y = 15

Thus, x = 9 and y = 15.

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