Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
14.6k views
in Measures of Central Tendency by (31.2k points)
closed by

If median of the following distribution is 27, then find the values of x and y.

Class-interval 0-10 10-20 20-30 30-40 40-50 50-60 Total
Frequency 5 x 20 14 y 8 68

1 Answer

+1 vote
by (35.3k points)
selected by
 
Best answer

Given: N = 68

⇒ 47 + x + y = 68

⇒ x + y = 68 – 47

⇒ x + y = 21 ……..(i)

Now \(\frac { N }{ 2 }\) = \(\frac { 68 }{ 2 }\) = 34

Median of distribution is 27 which lies is class-interval 20 – 30.

∴ Median class 20 – 30

l = 20, c = 5 + x, f = 20 and h = 10

⇒ 69 – x = 2 × 27

⇒ x = 69 – 54 = 15

Putting value of x in eqn. (i),

15 + y = 21

⇒ y = 21 – 15 = 6

Thus, x = 15, y = 6

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...