Total number of notes in the boxes A and B
= 25 + 50 = 75.
∴ Total number of all possible outcomes = 75
The number of notes on which Rs 1 is marked
= 19 + 45 = 64
Number of notes on which Rs 1 is not marked
= 75 – 64 = 11
Let the event that the note contains some thing else but Rs 1 be (A).
∴ The number of favourable outcomes of event (A)
= 11.
⇒ P(A) = \(\frac { 11 }{ 75 }\)
Hence P(A) = \(\frac { 11 }{ 75 }\)