Tossing the die all possible outcomes
= 1, 2, 3, 4, 5, 6
∴ Total number of all possible outcomes =6
(i) The even digits are 2, 4, 6
∴ The number of favourable outcomes = 3
∴ Required probability = \(\frac { 3 }{ 6 }\) = \(\frac { 1 }{ 2 }\)
(ii) The digits more than 3 are 4, 5, 6
∴ The number of favourable outcomes = 3.
∴ Requred probability = \(\frac { 3 }{ 6 }\) = \(\frac { 1 }{ 2 }\)
(iii) The digit between 3 and 6 are 4 and 5.
∴ The number of favourable outcomes = 2
∴ Required probability = \(\frac { 2 }{ 6 }\) = \(\frac { 1 }{ 3 }\)