Given that the base contains 30 discs.
(i) The two digits number 1 to 30
= 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30
The number of favourable outcomes = 21
The total number of all possible outcomes = 30
The probability that the disc drawn has a two digits number
= \(\frac { 21 }{ 30 }\) = \(\frac { 7 }{ 10 }\)
(ii) The perfect square numbers in 1 to 30
= 1, 4, 9, 16, 25.
The number of favourable outcomes = 5
Total number of all possible outcomes = 30
∴ The probability that the disc drawn contains a perfect square number
= \(\frac { 5 }{ 30 }\) = \(\frac { 1 }{ 6 }\)
