The number of red, white and blue balls in the bag are x, 2x and 3x respectively.
Total number of balls = 24
⇒ x + 2x + 3x = 24
6x = 24
x = \(\frac { 24 }{ 6 }\) = 4
∴ Red balls = 4
White balls
= 2 × 4 = 8
And blue balls
= 3 × 4 = 12
Total number of all possible outcomes = 24.
(i) Number of balls which are not red
= 8 + 12 = 20
∴ The favourable outcomes of not a red ball = 20
∴ The probability that the ball drawn is not red
= \(\frac { 20 }{ 24 }\) = \(\frac { 5 }{ 6 }\)
(ii) The number of favourable outcomes of the ball drawn is white = 8.
∴ The probability that the drawn ball is white
= \(\frac { 8 }{ 24 }\) = \(\frac { 1 }{ 3 }\)