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in Mathematics by (60.8k points)

A bag contains 5 red balls, 8 white balls, 4 green balls and 7 black balls. If one ball is drawn at random, find the probability that it is

(i) Black

(ii) Not red

(iii) Green

1 Answer

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Best answer

Number of red balls in the bag = 5

Number of white balls in the bag = 8

Number of green balls in the bag = 4

Number of black balls in the bag = 7

∴ Total number of balls in the bag = 5 + 8 + 4 + 7 = 24.

Drawing balls randomly are equally likely outcomes.

∴  Total number of possible outcomes = 24

Now,

(i) There are 7 black balls, hence the number of such favourable outcomes = 7

∴ Probability of drawing a black ball

(ii) There are 5 red balls, hence the number of such favourable outcomes = 5.

∴  Probability of drawing a red ball

∴ Probability of drawing not a red ball = P (Not Red ball) = 1 - 5/24 = 19/24

(iii) There are 4 green balls.

∴ Number of such favourable outcomes = 4

Probability of drawing a green ball

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