∵ AB || EF (given)
Also draw a line through P parallel to AB or EF
∴ 125°+ ∠APQ = 180°
(sum of the interior angles on the same side of a transversal is 180°)
⇒ ∠APQ = 180°- 125°
⇒ ∠APQ = 55°
Also PQ || EF (by const.)
∠QPE + 141°= 180°
(reason as above )
⇒ ∠QPE = 39°
∴ ∠x = 55° + 39° = 94°
and ∠y = 360° – 94° = 266°