Steps of Construction:
(i) 150° = 189° – \(\frac { 1 }{ 2 }\) x 60 = 180° – 30°
First draw ∠AOC = 60° then draw the bisector of ∠AOC.
Hence ∠BOP = 150° is the required angle.
(ii) Let OB be a line segment and at O construct an angle of 90°. With this vertical line construct an angle of 15° which gives required ∠BOP = 105°.
(iii) Let OB be a straight line and at O draw an angle of 60° and 90° then draw bisector of these two angles, which is the required ∠BOP = 75°.