Question

Sunita is half the age of her mother Geeta. Find their ages

(i) after 4 years.

(ii) before 3 years.

Answer 1

Let the present age of Sunita be x years.
The present age of her mother Geeta = 2(Sunita’s present age) = 2x years.

(i) After 4 years,

Sunita’s age = (x + 4) years

Geeta’s age = (2x + 4) years

(ii) Before 3 years,

Sunita’s age = (x – 3) years

Geeta’s age = (2x – 3) years.