Join Sarthaks eConnect Today - Largest Online Education Community!
0 votes
4 views
ago in Commercial Mathematics by (36.4k points)
closed ago by

Find the missing number in the box [ ] in the proportion:

16/36 = [ ]/63 = 36/[ ] = [ ]/117

1 Answer

+1 vote
ago by (37.1k points)
selected ago by
 
Best answer

Consider the first two ratios 16/36 = [ ]/63

Let us assume the missing number be P

Then, 16/36 = P/63

By cross multiplication we get,

P = (16 × 63)/36

P = 1008/36

Divide both numerator and denominator by 36.

P = 28

Therefore, 16/36 = [28]/63

Now, consider the middle two ratios, 28/63 = 36/[ ]

Let us assume the missing number be Q,

Then, 28/63 = 36/Q

By cross multiplication we get,

Q = (36 × 63)/28

Q = 2268/28

Divide both numerator and denominator by 28.

Q = 81

Therefore, 28/63 = 36/[81]

Consider the last two ratios 36/81 = [ ]/117

Let us assume the missing number be R

Then, 28/63 = R/117

By cross multiplication we get,

P = (28 × 117)/63

P = 3276/63

Divide both numerator and denominator by 63.

P = 52

Therefore, 36/81 = [52]/117

So, 16/36 = [28]/63 = 36/[81] = [52]/117

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...