(1) Uniformly accelerated motion, since the slope of the velocity-time graph is positive and uniform.
(2) It represents acceleration.
(3) The area below the velocity-time graph and time axis represents the distance covered.
(4) The area covered in 15 s i.e., area of triangle OBC gives the distance covered in 15 s.
∴ Distance covered
= \(\frac{1}{2}\) x BC x OC
= \(\frac{1}{2}\) x 30 x 15 Distance
= 225 m.
