Question

A stone of 1 kg is thrown with a velocity of 20 ms^-2 across the frozen surface of a lake and comes to rest after travelling a distance of 50 m. What is the force of friction between the stone and the ice?

Answer 1

Mass of stone (m) = 1kg;

Distance covered (s) = 50 m;

Initial velocity (u) = 20 ms^-1;

Final velocity (ν) = Zero;

Acceleration of the stone (a) =?

Force of friction (F) =?

Using the third equation, we have

Minus sign shows that the force of friction acts in the opposite direction.