Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
12.8k views
in Force and Motion by (48.1k points)
closed by

A motor car starting from rest moves with uniform acceleration and attains a velocity of 8 ms in 8 s. It then moves with uniform velocity and is finally brought to rest in 32 m under uniform retardation. The total distance covered by the car is 464 m. Find the value of acceleration, retardation and the total time is taken.

1 Answer

+1 vote
by (49.4k points)
selected by
 
Best answer

The figure shows the velocity-time graph. OA shows uniform acceleration; BC, uniform retardation and AB, the uniform velocity.

Now the area of velocity-time graph is equal to the distance covered.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...