Electrostatic Potential

Question

There is one uniformly charged hollow metal sphere of radius r. The potential difference between a point on the surface of this sphere and a point at a distance 2r from the surface is V. What will be the electric field intensity at a point at a distance 3r from the centre?

Answer 1

Let centre of the hollow sphere(of radius r) is O and potential at centre is V_{​​​​​​o}​​​​​.

Let point is P from where centre is at fistance 2r and potential at this point is V_​​​​​​p.

According to the question    V_{​​​​​​o}​​​​​-Vp=V

Now V_{​​​​​​o} =kq/r ,where q is the charge on hollow sphere.

V_P=kq/2r

Vo-Vp=(kq/2r)=V        q=(2rV/k)

Electric field at distance 3r from centre is  kq/r² 

Putting value of q here we get 

E=2V/r This is the final answer.

I hope it helps     

Comments

This answer is totally wrong

Answer 2

Let centre of the hollow sphere(of radius r) is O and potential at centre is V_{​​​​​​o}​​​​​.

Let point is P from where centre is at fistance 2r and potential at this point is V_​​​​​​p.

According to the question    V_{​​​​​​o}​​​​​-Vp=V

Now V_{​​​​​​o} =kq/r ,where q is the charge on hollow sphere.

V_P=kq/2r

Vo-Vp=(kq/2r)=V        q=(2rV/k)

Electric field at distance 3r from centre is  kq/r² 

Putting value of q here we get 

E=2V/r This is the final answer.

I hope it helps     

Comments

This is wrong check again