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A person clapped his hands near a cliff and heard the echo after 5 seconds. What is the distance of the cliff from the person if the speed of sound V is taken as 346 m/sec.

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Given V = 346 m/s, t = 5 second

Distance travelled = V x t

S = 346 x 5 = 1730 m i.e., in 5 seconds, the sound has to travel twice the distance between the cliff and the person. Thus, the distance between the cliff and the person

\(\frac{1730}{2}\) = 865 metres

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