Question

A ship sends out ultrasound that returns from the seabed and is directed after 3.42 s. If the speed of ultrasound through seawater is 1531 m/sec. What is the distance of the seabed from the ship?

Answer 1

Given: Time between transmission and
detection t = 3.42 sec

Speed of ultrasound in seawater V = 1531 m/s.

Let the depth of sea is d then distance travelled by ultrasound wave

2 d = speed of sound x time

i.e. 2d = V x t

2d = 1531 x 3.42

d = \(\frac{1531\times 3.42}{2}=\frac{5236}{2}\)

d = 2618

Thus, the distance of the sea bed from the ship is 2618 m.