Given: Time between transmission and
detection t = 3.42 sec
Speed of ultrasound in seawater V = 1531 m/s.
Let the depth of sea is d then distance travelled by ultrasound wave
2 d = speed of sound x time
i.e. 2d = V x t
2d = 1531 x 3.42
d = \(\frac{1531\times 3.42}{2}=\frac{5236}{2}\)
d = 2618
Thus, the distance of the sea bed from the ship is 2618 m.