Given: CD || AE and CY || BE
To prove: ar (∆CBX) = ar (∆AXY)
Proof: Since, ∆ABC and ∆BAY both lie on the same base AB and between the same parallel AB and CY.
ar (∆ABC) = (∆BAY)
⇒ ar (∆ABX) + ar (∆CBX) = ar (∆ABX) + ar (∆AXY)
⇒ ar (∆CBX) = ar (∆AXY)
[Eliminating ar (∆ABX) from both sides]
Hence proved.